@Wonder_Woman said:
I'm gambling on the step ahead being the playfair cipher, as I'm starting to think the 5 character "words" in the instructions should be used in a grid
EDIT: And, as we've previous seen, I'm a glutton for wasting a ton of time on things when it's much simpler than I anticipated.
@Wonder_Woman said:
I'm gambling on the step ahead being the playfair cipher, as I'm starting to think the 5 character "words" in the instructions should be used in a grid
EDIT: And, as we've previous seen, I'm a glutton for wasting a ton of time on things when it's much simpler than I anticipated.
Okay I'm going to step in here because you're probably going to play a pivotal role in this actually being solved if it is solved, and we're already three hours in (and it's not looking good.) It's not the playfair cipher. There are some indirect connections, similarities in purpose. There's a reason for the grouping for both. Both the playfair and the other were used during an important time period.
@Wonder_Woman said:
I'm gambling on the step ahead being the playfair cipher, as I'm starting to think the 5 character "words" in the instructions should be used in a grid
EDIT: And, as we've previous seen, I'm a glutton for wasting a ton of time on things when it's much simpler than I anticipated.
Okay I'm going to step in here because you're probably going to play a pivotal role in this actually being solved if it is solved, and we're already three hours in (and it's not looking good.) It's not the playfair cipher. There are some indirect connections, similarities in purpose. There's a reason for the grouping for both. Both the playfair and the other were used during an important time period.
@Wonder_Woman said:
I'm gambling on the step ahead being the playfair cipher, as I'm starting to think the 5 character "words" in the instructions should be used in a grid
EDIT: And, as we've previous seen, I'm a glutton for wasting a ton of time on things when it's much simpler than I anticipated.
Okay I'm going to step in here because you're probably going to play a pivotal role in this actually being solved if it is solved, and we're already three hours in (and it's not looking good.) It's not the playfair cipher. There are some indirect connections, similarities in purpose. There's a reason for the grouping for both. Both the playfair and the other were used during an important time period.
Vigenère cipher?
That's what I was thinking previously, but I thought I was the one who wasn't on the right track. Maybe I'm still not...
Thinking about the differences between a VirMach deal thread and what's going on in the other OGF thread made me chuckle a little bit. "We've doubled your bandwidth!" versus "here's a cipher, you have 10 hours. This WW2 museum photo will help."
@VirMach said:
Thinking about the differences between a VirMach deal thread and what's going on in the other OGF thread made me chuckle a little bit. "We've doubled your bandwidth!" versus "here's a cipher, you have 10 hours. This WW2 museum photo will help."
@VirMach said:
Thinking about the differences between a VirMach deal thread and what's going on in the other OGF thread made me chuckle a little bit. "We've doubled your bandwidth!" versus "here's a cipher, you have 10 hours. This WW2 museum photo will help."
You can double the timeline to break the cipher
And double the discount and double the clues to break the cipher :P
@VirMach said:
Thinking about the differences between a VirMach deal thread and what's going on in the other OGF thread made me chuckle a little bit. "We've doubled your bandwidth!" versus "here's a cipher, you have 10 hours. This WW2 museum photo will help."
You can double the timeline to break the cipher
And double the discount and double the clues to break the cipher :P
Virmach can also double the complexity of the cipher
The only thing I found is the encryption was done using substitution cipher. However, combination of two different algorithms of this approach makes super hard decrypting.
The repetition of the message key was a weakness of the Enigma system and was the starting point of Rejewski's attack. Specifically, there was a relationship between the first and fourth letters of the initial six-letter message, as well as between the 2nd and 5th, and the 3rd and 6th. If he got enough intercepted messages Rejewski could compile a table of correspondences between the first and fourth letters under the current day key, eg the letters abcdefghijklmnopqrstuvwxyz would be turned into qaweszxdrtfcvgyuhbnjiokmlp. He would compile similar tables using the 2nd and 5th positions, and the 3rd and 6th. Rejewski looked for patterns in these tables and focused on cycle length. Thus B might be encrypted as G, G as F, F as R and then R as B, completing a cycle of length 5.
That's odd because both mine and yours are AS8100 with the same Prefix Registrant.
Maybe try a different HE server and see if it works.
Negative Captain, none worked.
Give me a minute and I'll try to make a new tunnel and see what happens.
EDIT: You are correct. I tried to add a new HE IPv6 tunnel to a new VPS in QuadraNet Los Angeles and it gave me the same message that you received. "This network is restricted"
@CMunroe said:
Im wondering if maybe someone has a tunnel on the same IP under a different account.
I don't think it has to do with your IP as I got the same message on a new VPS. Old tunnels still work fine.
Thanks for the heads up, I know now not to delete any of the old tunnels.
@FrankZ said: EDIT: Ok, Wonder_Woman said this better a hour ago. So I am well behind the leader.
I'm ahead, I'm finishing up my era-accurate Bombe machine in Python while I eat dinner. Well okay that's also unfair taking all the credit since ChatGPT is doing most (all) the work. Have no idea how long it'll take though, it's probably better if the clues are used.
Edit -- wait a minute this isn't even correct. I think I'm missing my rings or maybe it's just not being displayed. Hmmm...
@FrankZ said: EDIT: Ok, Wonder_Woman said this better a hour ago. So I am well behind the leader.
I'm ahead, I'm finishing up my era-accurate Bombe machine in Python while I eat dinner. Well okay that's also unfair taking all the credit since ChatGPT is doing most (all) the work. Have no idea how long it'll take though, it's probably better if the clues are used.
@FrankZ said: EDIT: Ok, Wonder_Woman said this better a hour ago. So I am well behind the leader.
I'm ahead, I'm finishing up my era-accurate Bombe machine in Python while I eat dinner. Well okay that's also unfair taking all the credit since ChatGPT is doing most (all) the work. Have no idea how long it'll take though, it's probably better if the clues are used.
It would be nice to at least have cuteness as a redeeming factor. :'(
There are some configuration options for the decoder:
Rotors ⚙ (from left to right) (Walzenlage)
Reflector ⇄ (UmKehrWalze)
Positions of rings ∘ (Ringstellung)
Positions of rotors ⌖ (Grundstellung)
Connections pairs (Steckerverbindungen)
Trying various combinations, and guessing stuff, but it's really a stretch
see one position to three five ring a two
Rotors: "see" = C?
Positions of rotors: "position to" = 5, 5, 5? 2, 3, 5?
Position of rings: "ring a" = A?
We're running out of time so yes, "see" = C
The C is the UKW reflector. The rotors are I through V. Positions are 1 (A) through 26 (Z) and rings are 1 (A) through 26 (Z) so these are a lot more important to solve than the reflector (since there's 26 of them per rotor.) This is for Enigma I which corresponds to the Bombe machine photo I showed (that one cracked Enigma I, it's the one made by Alan Turing.)
My bruteforcer is pretty much useless unless you know more details from the clues, otherwise it'll take forever to run. I'm going to add settings for it just in case you guys have most of the stuff but not all of it and share the code if you're interested. If you have all of it then you can pretty much decrypt it in a second.
The C is the UKW reflector. The rotors are I through V. Positions are 1 (A) through 26 (Z) and rings are 1 (A) through 26 (Z) so these are a lot more important to solve than the reflector (since there's 26 of them per rotor.) This is for Enigma I which corresponds to the Bombe machine photo I showed (that one cracked Enigma I, it's the one made by Alan Turing.)
My bruteforcer is pretty much useless unless you know more details from the clues, otherwise it'll take forever to run. I'm going to add settings for it just in case you guys have most of the stuff but not all of it and share the code if you're interested. If you have all of it then you can pretty much decrypt it in a second.
Cool, that takes away a bit of the guesswork, although technically I had already guessed at all of that. Just nice to know I was right.
The C is the UKW reflector. The rotors are I through V. Positions are 1 (A) through 26 (Z) and rings are 1 (A) through 26 (Z) so these are a lot more important to solve than the reflector (since there's 26 of them per rotor.) This is for Enigma I which corresponds to the Bombe machine photo I showed (that one cracked Enigma I, it's the one made by Alan Turing.)
My bruteforcer is pretty much useless unless you know more details from the clues, otherwise it'll take forever to run. I'm going to add settings for it just in case you guys have most of the stuff but not all of it and share the code if you're interested. If you have all of it then you can pretty much decrypt it in a second.
Cool, that takes away a bit of the guesswork
Also important to know that for the position and rings, you can either use letters or numbers. A = 1, and so on. That knowledge is important for the clues to work.
The C is the UKW reflector. The rotors are I through V. Positions are 1 (A) through 26 (Z) and rings are 1 (A) through 26 (Z) so these are a lot more important to solve than the reflector (since there's 26 of them per rotor.) This is for Enigma I which corresponds to the Bombe machine photo I showed (that one cracked Enigma I, it's the one made by Alan Turing.)
My bruteforcer is pretty much useless unless you know more details from the clues, otherwise it'll take forever to run. I'm going to add settings for it just in case you guys have most of the stuff but not all of it and share the code if you're interested. If you have all of it then you can pretty much decrypt it in a second.
Cool, that takes away a bit of the guesswork
Also important to know that for the position and rings, you can either use letters or numbers. A = 1, and so on. That knowledge is important for the clues to work.
The C is the UKW reflector. The rotors are I through V. Positions are 1 (A) through 26 (Z) and rings are 1 (A) through 26 (Z) so these are a lot more important to solve than the reflector (since there's 26 of them per rotor.) This is for Enigma I which corresponds to the Bombe machine photo I showed (that one cracked Enigma I, it's the one made by Alan Turing.)
My bruteforcer is pretty much useless unless you know more details from the clues, otherwise it'll take forever to run. I'm going to add settings for it just in case you guys have most of the stuff but not all of it and share the code if you're interested. If you have all of it then you can pretty much decrypt it in a second.
Cool, that takes away a bit of the guesswork
Also important to know that for the position and rings, you can either use letters or numbers. A = 1, and so on. That knowledge is important for the clues to work.
Yep, I'm on board. I am expecting actual words to come out of this though, there's not like another encoding after this... right?
The C is the UKW reflector. The rotors are I through V. Positions are 1 (A) through 26 (Z) and rings are 1 (A) through 26 (Z) so these are a lot more important to solve than the reflector (since there's 26 of them per rotor.) This is for Enigma I which corresponds to the Bombe machine photo I showed (that one cracked Enigma I, it's the one made by Alan Turing.)
My bruteforcer is pretty much useless unless you know more details from the clues, otherwise it'll take forever to run. I'm going to add settings for it just in case you guys have most of the stuff but not all of it and share the code if you're interested. If you have all of it then you can pretty much decrypt it in a second.
Cool, that takes away a bit of the guesswork
Also important to know that for the position and rings, you can either use letters or numbers. A = 1, and so on. That knowledge is important for the clues to work.
I guess I'm still stuck here:
Italicized letters/words: see [UKW C] / one [enigma ver#] / position to [20 15] / three [C] / five [E] / ring a [1] / two [20 23 15]
Plus, @VirMach said it's rotors I-IV, meaning it's the 4-rotor version.
Using T, O, C, E as the position of rotors, and A, T, W, O as the position of the rings...still gets me gibberish for deciphering the instructions. This also assumes the instructions are encrypted with the same cipher as the codes.
Comments
Wonder Woman is (also) Obi Won ??
blog archives
i didn't sign up for da vinci code
I bench YABS 24/7/365 unless it's a leap year.
Vigenère cipher?
Oh no x2
That's what I was thinking previously, but I thought I was the one who wasn't on the right track. Maybe I'm still not...
Rare photo of @Wonder_Woman
I'm still playing around with it, but seems the most promising based on nothing but @VirMach's clues lol xD
Yeah, the "Instructions" do look like output from Enigma Machine, and the emphasized words might line up with rotor and ring settings
Yeah, it's just that there's a lot of missing information about what lines up where :P
Thinking about the differences between a VirMach deal thread and what's going on in the other OGF thread made me chuckle a little bit. "We've doubled your bandwidth!" versus "here's a cipher, you have 10 hours. This WW2 museum photo will help."
You can double the timeline to break the cipher
blog archives
And double the discount and double the clues to break the cipher :P
Virmach can also double the complexity of the cipher
blog archives
https://www.soler7.com/IFAQ/Enigma.htm
The picture may come from here
The only thing I found is the encryption was done using substitution cipher. However, combination of two different algorithms of this approach makes super hard decrypting.
Virmach Deals
It's much harder than reverse engineering a flutter app which was obfuscated
Virmach Deals
The repetition of the message key was a weakness of the Enigma system and was the starting point of Rejewski's attack. Specifically, there was a relationship between the first and fourth letters of the initial six-letter message, as well as between the 2nd and 5th, and the 3rd and 6th. If he got enough intercepted messages Rejewski could compile a table of correspondences between the first and fourth letters under the current day key, eg the letters abcdefghijklmnopqrstuvwxyz would be turned into qaweszxdrtfcvgyuhbnjiokmlp. He would compile similar tables using the 2nd and 5th positions, and the 3rd and 6th. Rejewski looked for patterns in these tables and focused on cycle length. Thus B might be encrypted as G, G as F, F as R and then R as B, completing a cycle of length 5.
Looking at enigma:
There are some configuration options for the decoder:
Rotors ⚙ (from left to right) (Walzenlage)
Reflector ⇄ (UmKehrWalze)
Positions of rings ∘ (Ringstellung)
Positions of rotors ⌖ (Grundstellung)
Connections pairs (Steckerverbindungen)
Trying various combinations, and guessing stuff, but it's really a stretch
Rotors: "see" = C?
Positions of rotors: "position to" = 5, 5, 5? 2, 3, 5?
Position of rings: "ring a" = A?
So I am thinking the comment
has to do with the rotor position ring on the enigma machine.
The instructions
look like the ciphertext expected for input to enigma. But I am getting nothing but garbage so far.
EDIT: Ok, Wonder_Woman said this better a hour ago. So I am well behind the leader.
Any more hints? greedy search is not really helpful.
Virmach Deals
I don't really need any more servers, but I feel like I'm letting you guys down! I've been plugging away at the hints into the Enigma Machine...
After this I'm going on a ....
Anyone got tunnelbroker working in LAX?
I tired, and I am being told the network is not allowed. Seems like a limit based on the DC?
I have it working on nodes LAXA031 & LAXA022
IP ranges are 104.234.36.xx & 141.11.209.xxx
too starving, i quit
Virmach Deals
Yep, tried again and got
This network is restrictedWhat IP range ?
141.11.93.xxx
I'm still not getting anywhere with this. Damn it, @VirMach!
That's odd because both mine and yours are AS8100 with the same Prefix Registrant.
Maybe try a different HE server and see if it works.
Negative Captain, none worked.
Give me a minute and I'll try to make a new tunnel and see what happens.
EDIT: You are correct. I tried to add a new HE IPv6 tunnel to a new VPS in QuadraNet Los Angeles and it gave me the same message that you received. "This network is restricted"
Im wondering if maybe someone has a tunnel on the same IP under a different account.
I don't think it has to do with your IP as I got the same message on a new VPS. Old tunnels still work fine.
Thanks for the heads up, I know now not to delete any of the old tunnels.
Weird!
Maybe too many people putting in tunnels, so rate limited?
I'm ahead, I'm finishing up my era-accurate Bombe machine in Python while I eat dinner. Well okay that's also unfair taking all the credit since ChatGPT is doing most (all) the work. Have no idea how long it'll take though, it's probably better if the clues are used.
Edit -- wait a minute this isn't even correct. I think I'm missing my rings or maybe it's just not being displayed. Hmmm...
It would be nice to at least have cuteness as a redeeming factor. :'(
Where I live, the word Bombe means a Toy Doll or a small figurine. Quite the opposite of the machine or its size. That image is haunting..
blog archives
I give up on the quest to crack the virbot enigma.
Good luck to whose who.van cracked and enjoy the coupons...
Save some foe me too
See you all layer.
Right after my post as i make my way to get some rest @VirMach will post the codes or additional clues
And I will 💯 miss some great ones.
Enjoy and thanks everyone
We're running out of time so yes, "see" = C
The C is the UKW reflector. The rotors are I through V. Positions are 1 (A) through 26 (Z) and rings are 1 (A) through 26 (Z) so these are a lot more important to solve than the reflector (since there's 26 of them per rotor.) This is for Enigma I which corresponds to the Bombe machine photo I showed (that one cracked Enigma I, it's the one made by Alan Turing.)
My bruteforcer is pretty much useless unless you know more details from the clues, otherwise it'll take forever to run. I'm going to add settings for it just in case you guys have most of the stuff but not all of it and share the code if you're interested. If you have all of it then you can pretty much decrypt it in a second.
I'm suffering
every time i revisit this thread, there's some new level of insanity going on with these codes
Cool, that takes away a bit of the guesswork, although technically I had already guessed at all of that. Just nice to know I was right.
Also important to know that for the position and rings, you can either use letters or numbers. A = 1, and so on. That knowledge is important for the clues to work.
What do I win if I get it?
Yep, I'm on board. I am expecting actual words to come out of this though, there's not like another encoding after this... right?
I guess I'm still stuck here:
Italicized letters/words: see [UKW C] / one [enigma ver#] / position to [20 15] / three [C] / five [E] / ring a [1] / two [20 23 15]
Plus, @VirMach said it's rotors I-IV, meaning it's the 4-rotor version.
Using T, O, C, E as the position of rotors, and A, T, W, O as the position of the rings...still gets me gibberish for deciphering the instructions. This also assumes the instructions are encrypted with the same cipher as the codes.